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0.12x=0.06x^2
We move all terms to the left:
0.12x-(0.06x^2)=0
We get rid of parentheses
-0.06x^2+0.12x=0
a = -0.06; b = 0.12; c = 0;
Δ = b2-4ac
Δ = 0.122-4·(-0.06)·0
Δ = 0.0144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.12)-\sqrt{0.0144}}{2*-0.06}=\frac{-0.12-\sqrt{0.0144}}{-0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.12)+\sqrt{0.0144}}{2*-0.06}=\frac{-0.12+\sqrt{0.0144}}{-0.12} $
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